If a, b, c are real numbers such that a + 2b + c = 4 then max. value of ab + bc + ca is
A
2
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B
4
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C
6
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D
8
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Solution
The correct option is B 4 Given (a+b)+(b+c)=4
But [(a+b)+(b+c)2]2≥[(a+b)(b+c)],A.M.≥G.M.
or (42)2≥ab+bc+ca+b2 4−b2≥∑ab or ∑ab≤4−b2 ∴ Max. value of ∑ab=4⇒(b)