If A,B,C are the angles of △ABC then cotA.cotB+cotB.cotC+cotC.cotA is equal to
A
0
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B
1
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C
2
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D
−1
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Solution
The correct option is B1 We know that tanA+tanB+tanC=tanA.tanB.tanC Dividing both sides by tanA.tanB.tanC ⇒1tanA.tanB+1tanB.tanC+1tanA.tanC=1 ⇒cotA.cotB+cotB.cotC+cotA.cotC=1 Therefore Answer is B