If a,b,c are the consecutive integers then the determinant ∣∣
∣
∣∣−a2abacab−b2bcacbc−c2∣∣
∣
∣∣ is divisible by
A
36
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B
144
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C
48
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D
none of these
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Solution
The correct options are A 36 B 144 D 48 Δ=∣∣
∣
∣∣−a2abacab−b2bcacbc−c2∣∣
∣
∣∣ =abc∣∣
∣∣−aaab−bbcc−c∣∣
∣∣ =a2b2c2∣∣
∣∣−1111−1111−1∣∣
∣∣ R1→R1+R2,R2→R2+R3 =a2b2c2∣∣
∣∣00220011−1∣∣
∣∣ Δ=4a2b2c2 Now, let a=1 then b=2,c=3 Δ=4×4×9 Hence, divisible by 36,144,48