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If a, b, c ar...

Question

If a,b,c are the roots of the equation x³-4x+24=0, then the equation who’s roots are b+c,c+a and a+b is given by?

x³ -4x +24=0

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x³ -6x +24=0

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x³ +4x -24=0

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x³ -4x -24=0

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none of these

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Solution

The correct option is D x³ -4x -24=0
Option (d)
a+b+c=0 ( coefficient of x² is 0) therefore
b+c=-a a+b=-c and a+c=-b
the equation who’s roots are –a,-b and –c is obtained by replacing x by –x in the equation
the required equation is (-x³)-4(-x)+24 = x³ -4x -24=0.

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