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Question

If a,b,c are the roots of x3+qx+r=0, form the equation whose roots are
b2c2,c2a2,a2b2.

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Solution

Given equation, x3+qx+r=0(1)

b2c2=a2b2c2a2=r2a2

y=r2x2x=ry.(2)

Substituting value of x from (2) in (1), we get

(ry)3+q(ry)+r=0

ry3+qry+r3=0y3=(qy+r2)=0

y3=q2y2+2qr2y+r4[Taking squares on both sides]

y3q2y22qr2yr4=0


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