If a- b- c are the roots of x3-x2-2004-0- Then the value of is - a-c a-b b-c- ab-c bc-a ca-b- a2-1 b2-1 c2-1 - is equal toA- -2 a c3-2 a c-4 a2 c-2 a b3-2 a b-4 a b cB- 2 a c3-2 a c-4 a2 c-2 a b3-2 a b-4 a b cC- -2 a c3-a c-4 a2 c-2 a b3-2 a b-4 a b cD- 2 a c-4 a2 c-2 a b3-2 a b-4 a b c

The correct option is A Since, x3 x2 2004 = 0 has three roots a, b, c Hence, nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; a + b ...

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Properties of Determinants

If a, b, c ar...

Question

If a, b, c are the roots of x³ - x² - 2004 = 0. Then the value of is equal to

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A_{2} + 3 B_{2} ⇌ 2 A B_{3} . . . K_{1}

A_{2} + C_{2} ⇌ 2 A C . . . K_{2}

B_{2} + \frac{1}{2} C_{2} ⇌ B_{2} C . . . . K_{3}

2 A B_{3} + \frac{5}{2} C_{2} ⇌ 2 A C + 3 B_{2} C

K_{1}, K_{2}

K_{3}

Divide:
$[(a^{2} + 2 a b + b^{2}) - (a^{2} + 2 a c + c^{2})]$ by $2 a + b + c$

a^{2} b c, b^{2} a c, c^{2} a b

12 a^{3} b c^{2}

12 a^{3} b c

12 a^{2} b c

2 a b + 3 a c + 2 a c

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