A is the set of the letters in the word college.
A={c,o,l,e,g}
B is the set of the letters in the word marriage.
B={m,a,r,i,g,e}
C is the set of the letters in the word luggage.
C={l,u,g,a,e}
B∪C={m,a,r,i,g,e,l,u}
A−(B∪C)={c,o} (1)
A−B={c,o,l}
A−C={c,o}
(A−B)∩(A−C)={c,o} (2)
From equation (1) and (2), A−(B∪C)=(A−B)∩(A−C).