Question

If A, B, C are three collinear points with coordinates $x$, $y$, $z$ respectively, such that $x<y<z$, then the order of the point is

• A. $B-A-C$
• B. $A-B-C$
• C. $A-C-B$
• D. $C-A-B$

Answer 1

The correct option is B $A-B-C$

Option (B), A-B-CAccording to the question;

$AB=|y-x|,BC=|z-y|,AC=|z-x|$

since,

$x<y=y-x$ is positive

Same,

$x<z=z-x$ is positive

$y<z=z-y$ is positive

$\therefore AB=y-x$, $Bx=z-y$, $ZC=z-x$

as, $AB+BC=y-x+z-y=z-x=AC$

Hence, $AB+BC=AC$

so, order of points $A-B-C$

Option B is correct.