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Question

If a,b,c are three consecutive positive integers and log(1+ac)=2k, then the value of k is

A
logb
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B
loga
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C
2
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D
1
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Solution

The correct option is A logb
Let a=n1,b=n,c=n+1, where n>1
Given, log(1+ac)=2k
log(1+n21)=2k
2logn=2k
logn=k
logb=k

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