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Question
If a, b, c are three positive integers such that a and b are in the ratio 3:4 while b and c are in the ratio 2:1, then which one of the following is a possible value of (a+b+c)?
If a, b, c are three positive integers such that a and b are in the ratio 3:4 while b and c are in the ratio 2:1, then which one of the following is a possible value of (a+b+c)?
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Solution
The correct option is C 207
We have a : b = 3 : 4 and b : c = 2 : 1
i.e. a : b : c = 3 : 4 : 2
Let, a = 3x; b = 4x; c = 2x
Then (a + b + c) = 3x + 4x + 2x = 9x
(a + b + c) is a multiple of 9.
Clearly, 207 is the only multiple of 9 among all options, hence is the correct answer.
207
We have a : b = 3 : 4 and b : c = 2 : 1
i.e. a : b : c = 3 : 4 : 2
Let, a = 3x; b = 4x; c = 2x
Then (a + b + c) = 3x + 4x + 2x = 9x
(a + b + c) is a multiple of 9.
Clearly, 207 is the only multiple of 9 among all options, hence is the correct answer.
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