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Question

If a, b, c be in arithmetic progression, then the value of (a+2bc)(2b+ca)(a+2b+c) is

A
16abc
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B
4abc
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C
8abc
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D
3abc
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Solution

The correct option is A 16abc
Since, a, b, c are in AP
2b=a+c
Now, (a+2bc)(2b+ca)(a+2b+c)
=(a+a+cc)(a+c+ca)(2b+2b)
=2a.2c.4b
=16abc

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