If a,b,c be positive and not all equal, then the value of the determinant ∣∣
∣∣abcbcacab∣∣
∣∣ is
A
–ve
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B
+ ve
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C
Depends on a, b, c
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D
None of these
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Solution
The correct option is A –ve Δ=−(a3+b3+c3−3abc)=−(a+b+c)(a2+b2+c2−ab−bc−ca)=−12(a+b+c)[(a−b)2+(b−c)2+(c−a)2],. which is clearly negative because of the given conditions.