If a- b- c- d and p are distinct real numbers such that a2-b2-c2 p2-2a b-b c-c d p-b 22-c2-d2-0-then a- b- c- d are ina GPbAPcHPd None of these

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Domain

If a, b, c, d...

Question

If a,b,c,d and p are distinct real numbers such that
(a²+b²+c²)p² -2(ab+bc+cd)p+(b2²+c²+d²)<=0,then a,b,c,d are in

a) GP
b)AP
c)HP
d)None of these

Open in App

Solution

Suggest Corrections

Similar questions

a, b, c, d

p

(a^{2} + b^{2} + c^{2}) p^{2} - 2 (a b + b c + c d) p + (b^{2} + c^{2} + d^{2}) \leq 0.

a, b, c, d

G . P .

(a^{2} + b^{2} + c^{2}) p^{2} - 2 (a b + b c + c d) p + (b^{2} + c^{2} + d^{2}) \leq 0

If a, b, c, d and p are different real numbers such that :

$(a^{2} + b^{2} + c^{2}) p^{2} - 2 (a b + b c + c d) p + (b^{2} + c^{2} + d^{2}) \leq 0$ , then show that a, b, c and d are in G.P.

a, b, c, d

p

(a^{2} + b^{2} + c^{2}) p^{2} - 2 (a b + b c + c d) p + (b^{2} + c^{2} + d^{2}) = 0.

a, b, c, d

p

(a^{2} + b^{2} + c^{2}) p^{2} - 2 (a b + b c + d c) p + (b^{2} + c^{2} + d^{2}) \geq 0

a, b, c, d

Join BYJU'S Learning Program