If A, B, C, D are four points in a space and |AB×CD+BC×AD+CA×BD|=λ(area of the triangle ABC). Then the value of λ is
4
Let D be origin and position vectors of A, B, and C be →a,→b and →c respectively.
⇒|−−→AB×−−→CD+−−→BC×−−→AD+−−→CA×−−→BD|
=|(→b−→a)×(−→c)+(→c−→b)×(−→a)+(→a−→c)×(−→b)
=2|→a×→b+→b×→c+→c×→a|
=2×2 area of Δ ABC
Hence, λ=4