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Question

If a,b,c,d are in continued proportion, prove that a:b+d=c3:c2d+d3.

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Solution

ab=bc=cd=k, then
a=bk=ck2=dk3 and b=ck=dk2 and c=dk
L.H.S. =ab+d=dk3dk2+d=k3k2+1
R.H.S. =c3c2d+d3=d3k3d2k2d+d3=k3k2+1
L.H.S. = R.H.S.

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