Both (a) and (b)
abcd>b2c2 or ad > bc. Hence answer (b) is true.
Now A.M. between a and c = 12(a+c)
Now as A.M. > H.M. so here ⇒ a + c > 2b ....(iii)
And c is H.M. between b and d ⇒ b + d > 2c .....(iv)
Adding (iii) and (iv), we get
(a+c)+(b+d) > 2(b+c) ⇒ a + d > b + c
Hence answer (a) is true. So both (a) and (b) are correct.