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Question

If A,B,C&D are the angles of a cyclic quadrilateral ABCD, then value of
cosA+cosB+cosC+cosD+1 is equal to :-

A
sin2A+cos2A
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B
sin2B+cos2B
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C
sin2A+sin2B
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D
cos2A+cos2B
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Solution

The correct options are
A sin2A+cos2A
B sin2B+cos2B
We have,
A+C=1800B+D=1800A=πCcosB=cosDcosA=cosC,
cosA+cosC+cosB+cosD=0cosA+cosB+cosC+cosD+1=1
We have,
sin2A+cos2A=1
Also sin2B+cos2B=1.


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