If $A + B > C + D, B + E = 2 C$ and $C + D > B + E$ , then which among the following options necessarily holds true:

A + B > 2 C

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A + B > 2 D

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A + B > 2 E

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A > C

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Solution

The correct option is A $A + B > 2 C$
$A + B > C + D > B + E$
$A + B > B + E$
$A + B > 2 C (B + E = 2 C)$

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