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Question

If A,B,C,D be any four points and E and F be the mid-points of AC and BD, respectively, then AB+CB+CD+AD is equal to

A
3EF
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B
4EF
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C
4FE
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D
3FE
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Solution

The correct option is B 4EF
Solution:- (C) 4EF
ABCD is a quadrilateral.
Given that F is the mid-point of BD, we get
AB+AD=2AF.....(1)
Similarly CB+CD=2CF.....(2)[E is the mid point of AC]
Adding eqn(1)&(2), we have
AB+AD+CB+CD=2(AF+CF)
AB+AD+CB+CD=2((FA)+(FC))
AB+AD+CB+CD=2(FA+FC)
AB+AD+CB+CD=2(2FE)
AB+AD+CB+CD=2(2EF)
AB+AD+CB+CD=4EF


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