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B
a2+d2>b2+c2
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C
ac+bd>b2+c2
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D
ac+bd>b2+d2
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Solution
The correct option is Cac+bd>b2+c2 a,b,c,d be in H.P., then 1a,1b,1c,1d will be in A.P.
Therefore 1b−1a=1c−1b=1d−1c⇒b=2aca+c
G.M. between a and b = √ac.
Now as G.M > H.M., so here √ac>b or ac>b2.
Similarly √bd>c or bd>c2 Adding, ac+bd>b2+c2