If $\to a, \to b, \to c, \to d$ be the vectors represented by the sides of a quadrilateral, taken in order, then $\to a + \to b + \to c + \to d = 0 .$

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B True

Suggest Corrections

Similar questions

Q. If

\to a, \to b, \to c, \to d

be the vectors represented by the sides of a quadrilateral, taken in order, then

\to a + \to b + \to c + \to d = 0 .

Q. If

\to a, \to b, \to c

be the vectors represented by the sides of a triangle taken in order, then prove that

\to a + \to b + \to c = 0

Q. The quadrilateral formed by joining the midpoints of the sides of a quadrilateral ABCD, taken in order, is a rectangle, if
(a) ABCD is a Parallelogram
(b) ABCD is rectangle
(c) diagonals of ABCD are equal
(d) diagonals of ABCD are perpendicular to each other.

Q. The quadrilateral formed by joining the midpoints of the sides of a quadrilateral ABCD, taken in order, is a rhombus, if
(a) ABCD is a Parallelogram
(b) ABCD is rhombus
(c) diagonals of ABCD are equal
(4) diagonals of ABCD are perpendicular to each other.

If A,B,C,D be the angles of a cyclic quadrilateral, taken in order, prove that: $c o s (180^{\circ} - A) + c o s (180^{\circ} + B) - s i n (90^{\circ} + D) = 0$

Join BYJU'S Learning Program

If →a,→b,→c, →d be the vectors represented by the sides of a quadrilateral, taken in order, then →a+→b+→c+→d=0.

The correct option is B True

If $\to a, \to b, \to c, \to d$ be the vectors represented by the sides of a quadrilateral, taken in order, then $\to a + \to b + \to c + \to d = 0 .$