Question

If $a,b,c,d,e$ are in A.P., then the value of $4b+6c-4d-e$ is, given that value of $a=2$.

• A. $1$
• B. $5$
• C. $10$
• D. None of these

Answer 1

The correct option is C $10$

Let 'a' be the first term and 't' be common difference of the A.P

$\Rightarrow b=a+t,c=a+2t,d=a+3t,e=a+4t$

$\therefore 4b+6c-4d-e=4(a+t)+6(a+2t)-4(a+3t)-(a+4t)=5a=10$