Question

If $a,b,c,d,e,f$ are A.M.'s between $2$ and $12$, then the value of $a+b+c+d+e+f$ is

• A. $14$
• B. $42$
• C. $84$
• D. $106$

Answer 1

The correct option is B $42$

Given : $a,b,c,d,e,f$ are A.M.'s between $2$ and $12$
$a+b+c+d+e+f=\frac{6}{2}[2+12]=42$