If (a, b), (c, d), (e, f) are the vertices of a triangle such that a, c, e are in GP with common ratio r and b, d, f are in GP with common ratio s, then the area of the triangle is
A
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B
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C
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D
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Solution
The correct option is B Here, c = ar, e = ar2, d = bs, f = bs2 ∴Δ (Area of triangle) =12∣∣
∣∣ab1cd1ef1∣∣
∣∣=12ab(s−r)(s−1)(r−1)