If a, b, c, d, e, f, g and h are the consecutive integers such that d is a multiplicative identity of h and ad = –2, then [de ÷ ab + cf – (d + g + h)] equals
यदि a, b, c, d, e, f, g व h क्रमागत पूर्णांक हैं जबकि h का गुणात्मक तत्समक d है तथा ad = –2, तब [de ÷ ab + cf – (d + g + h)] बराबर है