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Question

If a, b, c, d, e, f, g and h are the consecutive integers such that d is a multiplicative identity of h and ad = –2, then [de ÷ ab + cf – (d + g + h)] equals

यदि a, b, c, d, e, f, gh क्रमागत पूर्णांक हैं जबकि h का गुणात्मक तत्समक d है तथा ad = –2, तब [de ÷ ab + cf – (d + g + h)] बराबर है

A
0
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B
–10
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C
1
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D
–9
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