If a:b::c:d, show that (2a+3b):(2c+3d)::(2a-3b):(2c-3d).
Proof of the given relation:
If ab=cd, then the property of componendo and dividendo implies that a+ba-b=c+dc-d.
Given proportional is equivalent to ab=cd.
⇒2a3b=2c3d(Multiplyingbothsidesby23)⇒2a+3b2a-3b=2c+3d2c-3d(bycomponendoanddividendo)⇒2a+3b2c+3d=2a-3b2c-3d(bycrossmultiplying)⇒(2a+3b):(2c+3d)::(2a-3b):(2c-3d)
Hence proved.
Please Use the Components of Proportion like Componendo and dividends etc
If (a+3b+2c+6d)(a-3b-2c+6d)=(a+3b-2c-6d)(a-3b-2c+2c-6d)
Prove that a:b::c:d