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Question

If a,b,cϵR and a2+b2abab+10 and α+β+γ=0, then
Δ=∣ ∣ ∣1cosγcosβcosγacosαcosαcosβb∣ ∣ ∣ equals

A
ab
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B
1
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C
0
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D
-1
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Solution

The correct option is A 0
a2+b2abab+10a2+b22ab+abab+10a=b=1
As α+β+γ=0
Let α=BC,β=CA,γ=AB
Δ=∣ ∣ ∣1cos(AB)cos(CA)cos(AB)1cos(BC)cos(BC)cos(CA)1∣ ∣ ∣

=∣ ∣1cosAcosB+sinAsinBcosCcosA+sinCsinAcosAcosB+sinAsinB1cosBcosC+sinBsinCcosBcosC+sinBsinCcosCcosA+sinCsinA1∣ ∣

=∣ ∣cosAsinA0cosBsinB0cosCsinC0∣ ∣∣ ∣cosAcosBcosCsinAsinBsinC000∣ ∣=0

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