Question

if a,b,c form a Pythagorian triplet such that a=squre root of 1
1225 and a=3b-1, then the value of c is equal to
1) 40
2) 38
3)32
4) 37

Answer 1

a = root(1225) = 35

given, a = 3b - 1
So, 35 = 3b - 1
3b = 35 + 1
3b = 36
b = 36 / 3
b = 12

Then, c = root(12^2 + 35^2)
= root(144 + 1225)
= root(1369)
= 37