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Question

If a,b,cR and a2+b2+c2=1, then ab+bc+ca lies in the interval

A
[12,2]
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B
[1,2]
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C
[12,1]
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D
[1,12]
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Solution

The correct option is C [12,1]
(a+b+c)201+2(ab+bc+ca)0ab+bc+ca12 (1)
And we know that
(ab)2+(bc)2+(ca)2022(ab+bc+ca)0ab+bc+ca1 (2)

From (1) and (2),
ab+bc+ca[12,1]

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