If a,b,c∈R and a≠b, then both the roots of the equation 2(a−b)x2−11(a+b+c)x−3(a−b)=0 are always
If the roots of the equation (a – b)x2 + (b – c)x + (c – a) = 0 are equal, then prove that 2a = b + c.