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Question

If a+b+c is equal to 0 , then find the value of a cube + b cube + c cube

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Solution

a^3 + b^3 + c^3 - 3abc = (a + b + c)(a 2 + b 2 + c 2 - ab - bc - ca) this is the equation,here
a+b+c=0 so, a^3+b^3+c^3-3abc=0
a^3+b^3+c^3=3abc

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