If a,b,c,p,q,r are three complex numbers such that pa+qb+rc=1+i and ap+bq+cr=0 then value of p2a2+q2b2+r2c2 is
pa+qb+rc=1+i, ⇒(pa+qb+rc)2=(1+i)2=2i
⇒ p2a2+q2b2+r2c2+2(qrbc+rpca+pqab)=2i ⇒
⇒ p2a2+q2b2+r2c2+2abcpqr(ap+bq+cr)=2i
⇒ p2a2+q2b2+r2c2=2i