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Question

If a,b,c,p,q,r are three complex numbers such that pa+qb+rc=1+i and ap+bq+cr=0 then value of p2a2+q2b2+r2c2 is

A
0
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B
-1
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C
2i
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D
-2i
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Solution

The correct option is C 2i

pa+qb+rc=1+i, (pa+qb+rc)2=(1+i)2=2i

p2a2+q2b2+r2c2+2(qrbc+rpca+pqab)=2i

p2a2+q2b2+r2c2+2abcpqr(ap+bq+cr)=2i

p2a2+q2b2+r2c2=2i


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