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Question

If A+B+C=π then tanA+tanB+tanCtanAtanBtanC=

A
0
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B
2
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C
1
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D
-1
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Solution

The correct option is C 1
Given, A+B+C=πtan(A+B+C)=tanπ
tanA+tanB+tanCtanAtanBtanC1tanAtanBtanBtanCtanAtanC=0
tanA+tanB+tanCtanAtanBtanC=0
tanA+tanB+tanCtanAtanBtanC=1

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