If A - B - C - - then prove that sin 2A - sin 2B - sin 2C - 4sin Asin Bsin C

Consider the problem A + B + C = π sin ^2A + sin ^2B + sin ^2C [ =2sin ...

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Derivative of Standard Functions

If A + B + ...

Question

If $A + B + C = π$ , then prove that ${sin}^{2} A + {sin}^{2} B + {sin}^{2} C = 4 sin A sin B sin C$

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If : a+b+c=pie

then prove that : sin2A+sin2B+sin2C= 4sinAsinBsinC

A + B + C = π

{sin}^{2} A + {sin}^{2} B + {sin}^{2} C = 2 + 2 cos A \cdot cos B \cdot cos C

A + B + C = 180^{0}

sin 2 A + sin 2 B + sin 2 C = 4 sin A sin B sin C

A + B + C = 0

0

\neq π

sin 2 A + sin 2 B + sin 2 C = 2 (sin A + sin B + sin C) (1 + cos A + cos B + cos C)

Δ A B C

sin 2 A + sin 2 B + sin 2 C = 4 sin A sin B sin C

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