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Question

If a, b, c, x, y, z R, then ∣ ∣ ∣(ax)2(bx)2(cx)2(ay)2(by)2(cy)2(az)2(bz)2(cz)2∣ ∣ ∣=∣ ∣ ∣(k+ax)p(m+bx)p(n+cx)p(k+ay)p(m+by)p(n+cy)p(k+az)p(m+bz)p(n+cz)p∣ ∣ ∣
Find the value of k+m+n+p ?

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Solution

∣ ∣ ∣(ax)2(bx)2(cx)2(ay)2(by)2(cy)2(az)2(bz)2(cz)2∣ ∣ ∣
=∣ ∣ ∣a22ax+x2b22bx+x2c22cx+x2a22ay+y2b22by+y2c22cy+y2a22az+z2b22bz+z2c22cz+z2∣ ∣ ∣
=∣ ∣ ∣1xx21yy21zz2∣ ∣ ∣×∣ ∣ ∣a22a1b22b1c22c1∣ ∣ ∣ (Row
by Row)
=∣ ∣ ∣1xx21yy21zz2∣ ∣ ∣×(1)∣ ∣ ∣a22a1b22b1c22c1∣ ∣ ∣
=∣ ∣ ∣1xx21yy21zz2∣ ∣ ∣×(1)(1)∣ ∣ ∣12aa212bb212cc2∣ ∣ ∣ (C1C3)
=∣ ∣ ∣1xx21yy21zz2∣ ∣ ∣×∣ ∣ ∣12aa212bb212cc2∣ ∣ ∣
Multiplying row by row
=∣ ∣ ∣1+2ax+a2x21+2bx+b2x21+2cx+c2x21+2ay+a2y21+2by+b2y21+2cy+c2y21+2az+a2z21+2bz+b2z21+2cz+c2z2∣ ∣ ∣
=∣ ∣ ∣(1+ax)2(1+bx)2(1+cx)2(1+ay)2(1+by)2(1+cy)2(1+az)2(1+bz)2(1+cz)2∣ ∣ ∣
k=1, m=1, n=1, p=2
k+m+n+p=5

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