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Question

If A+B=π4, find (1+tanA)(1+tanB).

A
1
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B
32
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C
0
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D
2
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Solution

The correct option is D 2
Given, A+B=π4

tan(A+B)=tanπ4

tanA+tanB1tanAtanB=1

tanA+tanB=1tanAtanB

tanA+tanB+tanAtanB=1

1+tanA+tanB+tanAtanB=2

(1+tanA)+tanB(1+tanA)=2

(1+tanA)(1+tanB)=2

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