Given, A = {b, e, f, g} and B = {c, e, g, h}
(i) A ∪ B= {b, c, e, f, g, h} ... (1)
B ∪ A= {b, c, e, f, g, h} ... (2)
From (1) and (2) we have A ∪ B = B ∪ A
It is verified that union of sets is commutative.
(ii) A ∩ B= {e, g} ... (3)
B ∩ A= {e, g} ... (4)
From (3) and (4) we get, A ∩ B = B ∩ A
It is verified that intersection of sets is commutative.