Given, A = {b, e, f, g} and B = {c, e, g, h}
(i) A ∪ B= {b, c, e, f, g, h} ... (1) [1 mark]
B ∪ A= {b, c, e, f, g, h} ... (2) [1 mark]
From (1) and (2) we have A ∪ B = B ∪ A [½ mark]
It is verified that union of sets is commutative.
(ii) A ∩ B= {e, g} ... (3) [1 mark]
B ∩ A= {e, g} ... (4) [1 mark]
From (3) and (4) we get, A ∩ B = B ∩ A [½ mark]
It is verified that intersection of sets is commutative.