If a + b equal to 7 and ab equals to 12 then find the value of a minus b

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Solution

a+b=7, square both sides to get a^2+b^2+2ab=49…..(i)

ab=12 or 4ab=48…..(ii)

Subtract (ii) from (i)

a^2+b^2+2ab-4ab=49–48 or a^2+b^2-2ab=1

=> (a-b)^2=1 ; a-b=1

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