wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If α, β, γ and δ are the roots of x4+2x3+3x2+4x+5=0.
Find the equation whose roots are 1α,1β,1γ,1δ.


A

x4+3x3+2x2+4x+5=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

5x4+4x3+3x2+2x+1=0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

5x44x3+3x22x+1=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

x42x3+3x24x+5=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

5x4+4x3+3x2+2x+1=0


Given: x4+2x3+2x2+4x+5=0 ...(1) have roots as α, β, γ, δ.

Changing x to 1x

1x4+2x3+3x2+4x+5=0

5x4+4x3+3x2+2x+1=0 ...(2)

Roots of the equation (2) being the reciprocal of the roots of the equation (1) i.e., 1α, 1β, 1γ, 1δ.
Hence the required equation is
5x4+4x3+3x2+2x+1=0


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Transformation of Roots: Algebraic Transformation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon