wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a,b R, a> 0 and the quadratic equation ax2bx+1=0 has imaginary roots, then
a+b+1 is

A
positive
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
negative
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
depends on the sign of b.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A positive
f(x)=ax2bx+1
f(0)=1 (positive)
i.e. f(x)=ax2bx+1>0 (given ax2bx+1=0 has imaginary roots)
f(1)=a+b+1>0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature and Location of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon