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Negation of a Number

If a/b is the...

Question

If a/b is the additive inverse of c/d, then find the value of $\frac{a}{b} + \frac{c}{d}$

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Solution

$\frac{a}{b}$ is additive inverse of $\frac{c}{d}$
then $\frac{a}{b} + \frac{c}{d} = 0$

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Fill in the blanks :
$(i) Additive inverse of \frac{- 5}{- 12} = . . . . . . . (i i) \frac{- 5}{- 12} + its additive inverse = . . . . . . . (i i i) I f \frac{a}{b} i s a d d i t i v e i n v e r s e o f \frac{- c}{d}, then \frac{- c}{d} i s a d d i t i v e i n v e r s e o f . . . . . . Also \frac{a}{b} + \frac{(- c)}{d} + \frac{a}{b} = . . . . . . .$

Q. For every non-zero rational number

\frac{a}{b}

there exists a rational

\frac{c}{d}

\frac{a}{b} \times \frac{c}{d} = 1

, then the rational number

\frac{c}{d}

Q. The additive inverse of −5 is
(a) 5
(b) 0
(c) −4
(d) −6

Q. Additive inverse of −23 is
(a)

\frac{- 1}{23}

\frac{1}{23}

(c) 23
(d) −23

Q. Additive inverse of 28 is
(a)

\frac{1}{28}

(b) 0 (c) − 28 (d) 82

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