If a,b represent −−→AB,−−→BC respectively of a regular hexagon ABCDEF then −−→CD,−−→DE,−−→EF,−−→FA are
A
b-a, -a, -b, a-b
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B
A-b, a, b, b-a
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C
b-a, a, b, a-b
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D
A-b,-a,-b, b-a
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Solution
The correct option is A b-a, -a, -b, a-b ABCDEF is a regular hexagon ⇒→AD=2→BC,→ED=→AB,→FE=→BC,→FA=→DC
Given →AB=a,→BC=b
Now →AB+→BC+→CD=→AD⇒a+b+→CD=2→BC ⇒→CD=2b−(a+b)=b−a→DE=→BA=−→AB=−a,→EF=→CB=−→BC=−b→FA=→DC=−→CD=−(b−a)=a−b