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Question

If a,b represent AB,BC respectively of a regular hexagon ABCDEF then CD,DE,EF,FA are

A
b-a, -a, -b, a-b
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B
A-b, a, b, b-a
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C
b-a, a, b, a-b
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D
A-b,-a,-b, b-a
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Solution

The correct option is A b-a, -a, -b, a-b
ABCDEF is a regular hexagon
AD=2BC,ED=AB,FE=BC,FA=DC
Given AB=a,BC=b
Now AB+BC+CD=ADa+b+CD=2BC
CD=2b(a+b)=baDE=BA=AB=a,EF=CB=BC=bFA=DC=CD=(ba)=ab

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