The correct option is
C 5⇒5y−x=1.........(1)
⇒4x−10y=6........(2)
Multiply the (1) by 4
⇒20y−4x=4........(3)
Subtract the (3) and (2), we get
⇒10y=10
⇒y=1010=1
Substitute the value of y=1 in (1)
⇒5×1−x=1
⇒−x=1−5
⇒x=4
Let a=x and b=y, then
⇒a+b=4+1=5