Question

If a ball is dropped from a height of $40\text{m}$ and bounce back upto $60\%$ of the orginal height, then total distance travelled (in $\text{m}$) by the ball before coming to rest is

Answer 1

The distance travelled by the ball is
$S=40+2\times \left[40\right(0.6)+40(0.6{)}^2+\dots ]\Rightarrow S=40[1+2\times \left(\frac{0.6}{1-0.6}\right)]\therefore S=160\text{m}$