If a ball is dropped from a height of 40m and bounce back upto 60% of the orginal height, then total distance travelled (in m) by the ball before coming to rest is
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Solution
The distance travelled by the ball is S=40+2×[40(0.6)+40(0.6)2+…]⇒S=40[1+2×(0.61−0.6)]∴S=160m