If a bar magnet is cut lengthwise into 3 parts, the total number of poles will be
2
3
4
6
Hence, option D is correct.
The period of oscillation of a freely suspended long bar magnet is 4 seconds. If it is cut into two equal parts lengthwise, then the time period of each part will be
If a bar magnet is cut lengthwise into two parts, how many numbers of poles will be formed? [1 MARK]