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Question

If a bar magnet of moment is suspended in a uniform magnetic field ¯¯¯¯B it is given an angular deflection, w.r.t equilibrium position. Then the restoring torque on the magnet is


A
MBsinθ
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B
MBcosθ
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C
MBtanθ
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D
MB2sinθ
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Solution

The correct option is A MBsinθ
T=2(F×a/2×sinθ)
T=IABsinθ
m=IA
T=mBsinθ
12442_13533_ans.PNG

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