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Question

If a be one A.M and G1 and G2 be the G.Ms between b and c then G31+G32=

A
abc
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B
2abc
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C
3abc
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D
4abc
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Solution

The correct option is B 2abc
Lets consider b=p3,c=q3
G1=p2q
G2=pq2
(G1)3+(G2)3=(pq)3[p3+q3]
=bc(b+c)
a=(b+c)/2
2a=b+c
So the expression for (G1)3+(G2)3=2abc
Option B

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