If A be the maximum displacement of the particle from its equilibrium position then what is the distance travelled by a simple harmonic oscillator when it completes one oscillation?

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Solution

The correct option is D 4A
Suppose a particle is executing SHM between P and Q.The particle starts from eqilibrium position 'O' moves to amplitude position 'P', then the particle turn back and moves from 'P' to 'Q'. Finally the particle turns back again and return to equlibrium position 'O'. In this way particle completes one oscillation in one time period.

Total distance travelled while it goes from O -> P -> O -> Q -> O
=OP + PO + OQ + QO =A+A+A+A=4A

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